正则表达式的字符串替换方法

我有以下几行：

d:ProjectsqqqDevelopmentqqq.MySol1.sln
d:ProjectsqqqqqqDevelopmentqqqMySol2.sln
d:ProjectsqqqDevelopmentMyInstaller.sln
d:ProjectsqqqqqqDevelopmentMyInstaller.sln
d:ProjectsDevelopmentMyInstaller.sln

我需要一个正则表达式，这将导致捕获：

Line 1: Development and MySol1.sln
Line 2: Development and MySol2.sln
Line 3: Development and MyInstaller.sln
Line 4: Development and MyInstaller.sln
Line 5: Development and MyInstaller.sln

因此，一个正则表达式，将删除（忽略）字qqq从行。 我一直在试图与调节，并有部分的解决方案：

.*(?<A>.*).{3}(?<B>.*) 

这导致：

Line 1: Development and .MySol1.sln
Line 2: qqqDevelopment and MySol2.sln
Line 3: Development and nstaller.sln
Line 4: Development and nstaller.sln
Line 5: Development and nstaller.sln

因此，.{3}应固定

1.我认为，应该工作：

.*(?:qqq)?(?<A>.*)(?:qqq)?(?<B>.*)